翻訳と辞書
Words near each other
・ Jodie Bowering
・ Jodie Brett
・ Jodie Broughton
・ Jodie Campbell
・ Jodie Christian
・ Jodie Clatworthy
・ Jodie Connor
・ Jodie Cooper
・ Jodie Dallas
・ Jodie Davis
・ Jodie deSolla
・ Jodie Dibble
・ Jodie Dorday
・ Jodie Dry
・ Jodie Emery
Jodie Esquibel
・ Jodie Evans
・ Jodie Ferneyhough
・ Jodie Fields
・ Jodie Fisher
・ Jodie Forrest
・ Jodie Foster
・ Jodie Foster filmography
・ Jodie Gasson
・ Jodie Gates
・ Jodie Gold
・ Jodie Harrison
・ Jodie Harsh
・ Jodie Henry
・ Jodie Kenny


Dictionary Lists
翻訳と辞書 辞書検索 [ 開発暫定版 ]
スポンサード リンク

Jodie Esquibel : ウィキペディア英語版
Jodie Esquibel

Jodie Esquibel is an American mixed martial artist who competes in the Atomweight division. She is currently signed with Invicta FC.
==Mixed martial arts record==

|-
|Win
|align="center" |5–1
|Nicdali Rivera-Calanoc
|Decision (unanimous)
|Invicta FC 9: Honchak vs. Hashi
|
|align="center" | 3
|align="center" | 5:00
|Davenport, Iowa, United States
|
|-
|Win
|align="center" |4–1
|Jinh Yu Frey
|Decision (split)
|Invicta FC 8: Waterson vs. Tamada
|
|align="center" | 3
|align="center" | 5:00
|Kansas City, Missouri, United States
|
|-
|Loss
|align="center" |3–1
|Alex Chambers
|Submission (rear-naked choke)
|Invicta FC 5: Penne vs. Waterson
|
|align="center" | 1
|align="center" | 1:35
|Kansas City, Missouri, United States
|
|-
|Win
|align="center" |3–0
|Liz McCarthy
|Decision (split)
|Invicta FC 4: Esparza vs. Hyatt
|
|align="center" | 3
|align="center" | 5:00
|Kansas City, Kansas, United States
|
|-
|Win
|align="center" |2–0
|Amy Riehle
|Decision (unanimous)
|Jackson's MMA Series 7
|
|align="center" | 3
|align="center" | 5:00
|Albuquerque, New Mexico, United States
|
|-
|Win
|align="center" |1–0
|Brittany Horton
|TKO (head kick and punches)
|Jackson's MMA Series 4
|
|align="center" | 1
|align="center" | 3:59
|Albuquerque, New Mexico, United States
|
|-
|}
==References==


抄文引用元・出典: フリー百科事典『 ウィキペディア(Wikipedia)
ウィキペディアで「Jodie Esquibel」の詳細全文を読む



スポンサード リンク
翻訳と辞書 : 翻訳のためのインターネットリソース

Copyright(C) kotoba.ne.jp 1997-2016. All Rights Reserved.